3x-2=x^2+1

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Solution for 3x-2=x^2+1 equation: 



3x-2=x^2+1

We move all terms to the left:

3x-2-(x^2+1)=0

We get rid of parentheses

-x^2+3x-1-2=0

We add all the numbers together, and all the variables

-1x^2+3x-3=0

a = -1; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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